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A sum of money under compound interest doubles itself in 4 years. In how many years will it become 16 times itself? 

 

Option: 1

12 years


Option: 2

16 years


Option: 3

8 years


Option: 4

None of these


16 years 

 

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Posted by

Debjani Behera

A certain loan amounts, under compound interest, compounded annually earns an interest of Rs.1980 in the second year and Rs.2178 in the third year. How much interest did it earn in the first year?

Option: 1

Rs.1600


Option: 2

Rs.1800


Option: 3

 Rs.1900


Option: 4

None of these

 


xyz pqr abc year tt

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Posted by

wgqefiqyg

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Read the passage below and answer the following questions.

Cheating is considered a criminal offence under the Indian Penal Code. It is done to gain profit or advantage from another person by using some deceitful means. The person who deceives another knows for the fact that it would place the other person in an unfair situation. Cheating as an offence can be made punishable under Section 420 of the IPC. Scope of Section 415 Cheating is defined under Section 415 of the Indian Penal Code as whoever fraudulently or dishonestly deceives a person to induce that person to deliver a property to any person or to consent to retain any property. If a person intentionally induces a person to do or omit to do any act which he would not have done if he was not deceived to do so and the act has caused harm to that person in body, mind, reputation, or property, then the person who fraudulently, dishonestly or intentionally induced the other person is said to cheat. Any dishonest concealment of facts that can deceive a person to do an act that he would not have done otherwise is also cheating within the meaning of this section. Essential Ingredients of Cheating requires · deception of any person. Fraudulently or dishonestly inducing that person to deliver any property to any person or to consent that any person shall retain any property; or · intentionally inducing a person to do or omit to do anything which he would not do or omit if he were not so deceived, and the act or omission causes or is likely to cause damage or harm to that person in body, mind, reputation or property.

Deceit– a tort arising from an untrue or false statement of facts which are made by a person, recklessly or knowingly, with an intention that it shall be acted upon by the other person, who would suffer damages as a result. 

Fraud – a false or untrue representation of the fact, that is made with the knowledge of its falsity or without the belief in its truth or a reckless statement that may or may not be true, with an intention to induce a person or individual to act independent of it with the result that the person acts on it and suffers damages and harm. In other words, it is a wrong act or criminal deception with an intention to result in financial or personal gain.

Question :- D went to a moneylender, Z, for the loan. D intentionally pledges the gold article with Z taking the loan. D knows that the article is not made of gold. After a few days, D leaves the village. Decide.

Option: 1

-


Option: 2

D has committed cheating as well as fraud 
 


Option: 3

D has not committed the offence of cheating 

 


Option: 4

D has committed an act which is an offence of cheating as well as the tort of deceit


As per section 415 of IPC, D has intentionally pledged the gold article with Z, his intention is clearly to deceive Z and cause him financial loss hence D would be liable for the offence of Cheating. Actions of D are also held liable as a tort of deceit.

Hence option (d) is correct. 

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Posted by

Rishabh Jain

In angiosperm, the haploid, diploid and triploid structures of a fertilized embryo sac sequentially are:

Option: 1

Synergids, Primary endosperm nucleus and zygote


Option: 2

Antipodals, synergids, and primary endosperm nucleus


Option: 3

Synergids, Zygote and Primary endosperm nucleus


Option: 4

Synergids, antipodals and Polar nuclei


The correct option is Option 3) Synergids, Zygote, and Primary endosperm nucleus.

In angiosperms, the fertilized embryo sac, which is the female gametophyte, contains various structures at different ploidy levels after fertilization. These structures include synergids, zygote, and the primary endosperm nucleus.

Synergids: Synergids are haploid cells found within the embryo sac. They are located at the micropylar end and play a role in guiding the pollen tube to the embryo sac during fertilization.

Zygote: After the pollen tube reaches the embryo sac and delivers the male gametes, fertilization occurs. The fusion of the sperm cell with the egg cell results in the formation of a zygote. The zygote is the first cell of the sporophytic generation and is diploid (2n) in ploidy.

Primary endosperm nucleus: The primary endosperm nucleus, also known as the central cell, is located at the center of the embryo sac. It contains two polar nuclei and is involved in the formation of endosperm. After fertilization, the primary endosperm nucleus undergoes triple fusion with one sperm cell, resulting in the formation of a triploid (3n) primary endosperm nucleus.

Therefore, the correct sequence of haploid, diploid, and triploid structures in a fertilized embryo sac is Synergids, Zygote, and Primary endosperm nucleus, as stated in Option 3.

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Posted by

Gunjita

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A massless string connects two pulley of masses ' 2 \mathrm{~kg}' and '1 \mathrm{~kg}' respectively as shown in the figure.

The heavier pulley is fixed and free to rotate about its central axis while the other is free to rotate as well as translate. Find the acceleration of the lower pulley if the system was released from the rest. [Given, g=10 \mathrm{~m} / \mathrm{s}^2]

Option: 1

\frac{4}{3} \mathrm{~gm} / \mathrm{s}^2


Option: 2

\frac{3}{2} \mathrm{~gm} / \mathrm{s}^2


Option: 3

\frac{3}{4} \mathrm{~gm} / \mathrm{s}^2


Option: 4

\frac{2}{3} \mathrm{~gm} / \mathrm{s}^2


Not understanding sir 

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Posted by

Raju vittal nandi

The largest term in the expansion of  (3+2 x)^{50} \text {. where } x=\frac{1}{5} \text { is }

Option: 1

5^{\text {th }}


Option: 2

8^{\text {th }}


Option: 3

7^{\text {th }}


Option: 4

4^{\text {th }}


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Posted by

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In a common base amplifier circuit, calculate the change in base current if that in the emitter current is \mathrm{2mA\: and\: \alpha =0.98}
 

Option: 1

\mathrm{0.04\: mA}


Option: 2

\mathrm{1.96\: mA}


Option: 3

\mathrm{0.98\: mA}


Option: 4

\mathrm{2\: mA}


\mathrm{ \alpha=\frac{\Delta I_c}{\Delta I_e} \Rightarrow \Delta I_c=0.98 \times 2=1.96 \mathrm{~mA} }

\mathrm{ \Delta I_b=\Delta I_e-\Delta I_c=2-1.96=0.04 \mathrm{~mA}}

Hence option 1 is correct.

 

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Posted by

Ajit Kumar Dubey

In the experiment, calculate the acceleration due to gravity, By using simple pendulum, which have time period of 0.3 second is measured from time of 50 oscillation with a watch of one second resolution. When length is 5 cm known to 1 mm accuracy find accuracy in the 'g'

Option: 1

15.33 %


Option: 2

12.33 %


Option: 3

13 %


Option: 4

15.55 %


\begin{aligned} & T=2 \pi \sqrt{\frac{l}{g}} \\ & g=\frac{1}{4 \pi^2 l} \frac{T^2}{l}\Rightarrow \frac{\Delta g}{T}= \frac{2 \Delta T}{T}+\frac{\Delta l}{l} \\ & \frac{\Delta g}{g}=2 \times \frac{1}{50 \times 0.3}+\frac{1 \mathrm{~mm}}{5 \mathrm{~cm}} \\ & =0.1533 \\ & \frac{\Delta g}{g} \times 100=15.33 \% . \end{aligned}

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Posted by

Kshitij

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A sample of perfect gas is compressed isothermally to half its volume. If it is compressed adiabatically to the same volume, the final pressure of the gas will be

Option: 1

 more


Option: 2

less


Option: 3

same


Option: 4

more or less depending on the initial temperature of the gas


For isothermal compression, \mathrm{p_{2}=\frac{p V_{1}}{V_{2}}}

For adiabatic compression, \mathrm{p_{2}=p_{1}\left(\frac{V_{1}}{V_{2}}\right)^{\gamma}}

Since, \mathrm{\gamma=\frac{C_{p}}{C_{V}}>1}, hence \mathrm{p_{2}} will be more as compared to that of isothermal compression.

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Posted by

Rakesh

An ideal is taken through a cycle \mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{A}  as shown in Figure if the net heat supplied in the cycle is 5 \mathrm{~J}, then work done by the gas in the process \mathrm{C} \rightarrow \mathrm{A} is

Option: 1

-5 \mathrm{~J}


Option: 2

-10 \mathrm{~J}


Option: 3

-15 \mathrm{~J}


Option: 4

-20 \mathrm{~J}


Work done = area under the curve

10 \mathrm{~J} ; 5=\mathrm{W}_{\mathrm{CA}}+10$ or $\mathrm{W}_{\mathrm{CA}}=-5 \mathrm{~J}

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Posted by

Sayak

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